Answer:
![\text{Yes, If no more than a total of }(1)/(12)foot\text{ is needed for spacing between desks}](https://img.qammunity.org/2023/formulas/mathematics/college/xgebec2pko5sed3gcf6bs1uu95xbc3a1hx.png)
Step-by-step explanation:
Given that six office desks that are 7 1/12 feet long are to be placed together.
The length of the six desks is;
![\begin{gathered} 6*7(1)/(12) \\ =6*7+6*(1)/(12) \\ =42(6)/(12) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/bdh4sqa93pfi7lyxh06pfcvm1wlmoiuj1y.png)
Given that the wall is 42 7/12 feet long.
Then the length of the six desks is shorter than the length of the wall.
![42(7)/(12)-42(6)/(12)=(1)/(12)](https://img.qammunity.org/2023/formulas/mathematics/college/mj9g19jbmemoe94db3nbzdpplbo0c2nxjq.png)
Therefore, it will fit on the wall if no more than a total of 1/12 foot is needed for spacing between desks.
![\text{Yes, If no more than a total of }(1)/(12)foot\text{ is needed for spacing between desks}](https://img.qammunity.org/2023/formulas/mathematics/college/xgebec2pko5sed3gcf6bs1uu95xbc3a1hx.png)