Question

After traveling for 6.0 seconds, a runner reaches a speed of 12 m/s after startingfrom rest. What is the runner's acceleration?

Answer 1

Given data:

Initial speed of the runner as he starts from the rest;

`u=0`

Final speed of the runner;

`v=12\text{ m/s}`

Time taken;

`t=6.0\text{ s}`

The acceleration of the runner is given as,

`a=(v-u)/(t)`

Substituting all known values,

`\begin{gathered} a=\frac{(12\text{ m/s})-0}{(6.0\text{ s})} \\ =2\text{ m/s}^2 \end{gathered}`

Therefore, the acceleration of the runner is 2 m/s².