Question

pls help meHow many liters of NH3 are needed to react completely with 30.0 L of NO (at STP)?4NH3 (g)+ 6NO(g) 5N2(g)+ 6H2o(g)a.5.0 Lc.7.5 Lb.20.0 Ld.120.0 L

Answer 1

`20.0\text{ L}`

Step-by-step explanation:

Here, we want to get the volume of NH3 that will react with 30L of NO at STP

From the question, we have it that 4 moles of ammonia reacted 6 moles of NO

Thus, we have the mole ratio as 6 to 4

Thus, the volume of ammonia reacted would be:

`(4)/(6)*30\text{ = 20.0 L}`