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Which of the following rational expressions has the domain restrictions X = -6 and x = 1?

User Nox
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1 Answer

5 votes

The domain of the function is possible values of independant varaible such that function is defined or have real values.

So the expression


((x+2)(x-3))/((x-1)(x+6))

is not defined for x = -6 and for x = 1, as expression becomes undefined for this values of x (Denominator becomes 0).

So answer is,


((x+2)(x-3))/((x-1)(x+6))

Option B is correct.

User Radu Cugut
by
7.5k points

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