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Need helpp pls i don't know how to do it.

Need helpp pls i don't know how to do it.-example-1
User Kennet
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1 Answer

5 votes

Answer:

The value of angle QXS is;


m\measuredangle QXS=40^0

Step-by-step explanation:

From the given diagram in question 1:

We can see that angle QXT equals the sum of angle SXT and angle QXS;


m\measuredangle QXT=m\measuredangle SXT+m\measuredangle QXS

Given in the question is the value of angle SXT and angle QXS;


\begin{gathered} m\measuredangle SXT=4x+1 \\ m\measuredangle QXS=2x-2 \end{gathered}

Substituting the values into the equation above;


\begin{gathered} m\measuredangle QXT=m\measuredangle SXT+m\measuredangle QXS \\ m\measuredangle QXT=4x+1+2x-2 \\ m\measuredangle QXT=4x+2x+1-2 \\ m\measuredangle QXT=6x-1 \end{gathered}

Since angle QXT is equal to 125 degree, then;


\begin{gathered} m\measuredangle QXT=6x-1=125 \\ 6x-1=125 \\ 6x=125+1 \\ 6x=126 \\ (6x)/(6)=(126)/(6) \\ x=21 \end{gathered}

We can now substitute the value of x to get the value of angle QXS;


\begin{gathered} m\measuredangle QXS=2x-2 \\ m\measuredangle QXS=2(21)-2 \\ m\measuredangle QXS=42-2 \\ m\measuredangle QXS=40^0 \end{gathered}

Therefore, the value of angle QXS is;


m\measuredangle QXS=40^0

User Diesersamat
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