Question

The perimeter of a rectangular pool is 44 feet. The length is 8ft longer than the width. Find the dimensions.

Answer 1

Given:

A rectangular pool with the following measures,

Perimeter

Length = x + 8

Width = x

Let's determine the measure of its dimensions:

`\text{ Perimeter = 2L + 2W}`
`\text{ = 2(x + 8) + 2(x)}`
`\text{ 44 = 2x + 16 + 2x}`
`\text{ 44 = 4x + 16}`
`\text{ 44 - 16 = 4x}`
`\text{ 28 = 4x}`
`\text{ }(28)/(4)\text{ = }\frac{4x\text{ }}{4}`
`\text{ 7 = x}`

Let's now determine its dimensions,

Length = x + 8 = 7 + 8 = 15 ft.

Width = x = 7 ft.

Therefore, the dimension of the rectangular pool is Length = 15 ft. and Width =7 ft.