Question

I have a homework problem that I don’t even know where to start or what formulas to use

Answer 1

We will have the following:

a) The velocity after 5 seconds will be:

`v_f=v_o+at`

`v=2.79m/s+(9.8m/s^2)(5s)\Rightarrow v=51.79m/s`

So, the velocity after 5 seconds will be 51.79m/s.

b) We will have that the distance below the helicopter will be:

`d=(1)/(2)(v_0+v_f)t`
`d=(1)/(2)(2.79m/s+51.79m/s)(5s)\Rightarrow d=136.45m`

So, it will be 136.45 m below the helicopter.

c) We will have that the velocity and distance given that the helicopter is moving constantly at 2.79m/s will be:

`v=-2.79m/s+(9.8m/s^2)(5s)^2\Rightarrow v=46.21m/s`

So, the velocity would be 46.21 m/s.

`d=(1)/(2)(-2.79m/s+46.21m/s)(5s)\Rightarrow d=108.55m`

So, the distance would be 108.55 m below the helicopter.