Question

Solve the system using substitution. You can eliminate the decimals if you like, but you don’t have to. The solution will be the same in either case. {0.45x + 0.10y = 4.30 y = 22-x (x,y)= (_, _)

Answer 1

Case: System of equations

Method:

`\begin{gathered} 0.45x+0.10y=4.30....(1) \\ y=22-x....(2) \\ Substitute\text{ }y=22-x\text{ }into\text{ }eqn(1) \\ 0.45x+0.10y=4.30 \\ 0.45x+0.10(22-x)=4.30. \\ 0.45x+2.2-0.1x=4.30 \\ 0.45x-0.1x=4.3-2.2 \\ 0.35x=2.1 \\ x=(2.1)/(0.35) \\ x=(210)/(35) \\ x=6 \end{gathered}`

Put x = 6 in y= 22 -x

`\begin{gathered} y=22-x \\ y=22-6 \\ y=16 \end{gathered}`

Final answer:

(x,y) = (6, 16)