Question

in four hours, a hiker in a canyon goes from 892ft to 256 ft above the canyon floor. Find the hikers vertical speed.

Answer 1

From the given question, we can deduce the following information:

• Time, t = 4 hours

,

• The hiker goes from 892 ft to 256 ft above the canyon floor.

Let's find the vertical speed of the hiker.

To find the speed, apply the formula:

`speed=(dis\tan ce)/(time)`

To find the distance, we have:

Distance covered = 256 ft - 892 ft = -636 ft.

Hence, to find the vertical speed, we have:

`\begin{gathered} speed=(dis\tan ce)/(time) \\ \\ \text{speed}=(-636)/(4)=-159\text{ ft/h} \\ \end{gathered}`

Therefore, the vertical speed of the hiker is -159 feet per hour.

ANSWER: