Question

A5 kg box is at the top of a 2.7 m tall frictionless incline as shown in the diagram. It slides to the bottom of the incline, reaching a speed of 7.3m / s . What is the box's kinetic energy at the bottom of the incline? Whats the boxs ptential energy at the top of the incline?

Answer 1

Kinetic energy: 133.2 J

Potential energy: 132.3 J

Explanation:

Gven:

Mass (m) = 5 kg

Height (h) = 2.7 m

Speed (v) = 7.3 m/s

We calculate the kinetic energy and the potential energy using the respective formula in each case, as follows:

`\begin{gathered} E_k=(1)/(2)\cdot m\cdot v^2=(1)/(2)(5)(7.3)^2=133.2\text{ J} \\ \\ E_p=m\cdot g\cdot h=(5)(9.8)(2.7)=132.3\text{ J} \end{gathered}`

Therefore, the kinetic energy is equal to 133.2 joules and the potential energy is equal to 132.3 joules.