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Solve 9abs(3n-2) + 6 > 51 and graph on the number line

User KevinLeng
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1 Answer

4 votes

Solving the inequality,


\begin{gathered} 9\lvert3n-2\rvert+6>51 \\ \rightarrow9\lvert3n-2\rvert>45 \\ \rightarrow\lvert3n-2\rvert>5 \end{gathered}

Remember that if


\lvert u\rvert>a,a>0\Rightarrow u<-a\text{ or }u>a

This way, we get:


\begin{gathered} 3n-2<-5\rightarrow3n<-3\rightarrow n<-1 \\ 3n-2>5\rightarrow3n>7\rightarrow n>(7)/(3) \end{gathered}

As an interval, we get:


\: \mleft(-\infty\: ,\: -1\mright)\cup\mleft((7)/(3),\: \infty\: \mright)

In the number line, we get:

Solve 9abs(3n-2) + 6 > 51 and graph on the number line-example-1
User Rohitashv Singhal
by
8.1k points

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