Given the function :
![h(x)=\sqrt[3]{-x+2}](https://img.qammunity.org/2023/formulas/mathematics/college/yg5rw0x5ayc29s9m6deykcnefj8dv3gl4m.png)
To find which table represents the given function, let x with the numbers given in the table and find the corresponding value of h(x)
So, when x = 0
![h(0)=\sqrt[3]{0+2}=\sqrt[3]{2}](https://img.qammunity.org/2023/formulas/mathematics/college/ziq84ysf2uu0c0jlkt08xshkm999uirecr.png)
Now look to the tables which table has y = 3root of 2
We can deduce that the first two tables are wrong
Now, substitute with x = 2
![h(2)=\sqrt[3]{-2+2}=\sqrt[3]{0}=0](https://img.qammunity.org/2023/formulas/mathematics/college/go2v8fovzautimtwwrw72t8txsjazvzpi1.png)
So, this result will be agreed with the third table
so, the answer is: Table 3