1 Answer

R Pasha · Answer 1 · 2023-12-06T17:15:03+0000

According to work energy thereom, the work done on the car to accelerate is,

Plug in the known values,

$\begin{gathered} W=(1)/(2)(1200kg)(100km/h)^2(\frac{1000\text{ m}}{1\text{ km}})^2(\frac{1\text{ h}}{3600\text{ s}})^2(\frac{1\text{ J}}{1kgm^2s^(-2)})-_{}(1)/(2)(1200kg)(30km/h)^2(\frac{1000\text{ m}}{1\text{ km}})^2(\frac{1\text{ h}}{3600\text{ s}})^2(\frac{1\text{ J}}{1kgm^2s^(-2)}) \\ =462963\text{ J-}41667\text{ J} \\ =421296\text{ J} \end{gathered}$

The power output of the engine can be given as,

Substitute the values,

$\begin{gathered} P=\frac{421296\text{ J}}{10\text{ s}}(\frac{1\text{ W}}{1\text{ J/s}}) \\ =42129.6\text{ W} \end{gathered}$

Therefore, the power output of the engine is 42129.6 W.

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