Answer:
Step-by-step explanation:
The force of 80N is applied on sled at 53⁰
Its horizontal component = 80cos53
= 48.14 N .
Its horizontal component will pull forward the sled and friction will prevent its forward motion . As sled is moving with constant velocity , net force on it is zero .
Hence forward push = frictional force
Frictional force = 48.14 N.