Question: What is the equation of the line in standard form?
The standard form for a line is :
y = mx + b
where m is the slope and b is the intercept with y axis.
First, we are going to find the slope, choosing any two points on the line. For example (X1, Y1) = (-4,0) and (X2, Y2) = (0,3). Then, by definition the slope is:

so, our new line equation would be:

that is:

Now, we are going to find the y-intercept. This is also accomplished by picking two points on the line and solving for b. For example (X2, Y2) = (0,3). So, for above equation we have:

then

Then, we have b = 3.
Now, replacing the values of the slope and the intercept previously found, we obtain the equation of the line :

that is
