Question

Moles and mass and help with ratios eg 3:4 3:7

Answer 1

The balanced equation is:

`Mg_((s))+H_2O_((g))\to MgO_((s))+H_(2(g))`

The first step is to convert the given mass of magnesium to moles (MW=24.3g/mol):

`1g\cdot(1mol)/(24.3g)=0.04mol`

Now, use the ratio given by the chemical equation:

`0.04molMg\cdot(1molMgO)/(1molMg)=0.04molMgO`

Now, use the molecular weight of magnesium oxide to convert it to grams (MW=40.3g/mol):

`0.04mol\cdot(40.3g)/(1mol)=1.612g`

The maximum mass of magnesium oxide produced is 1.612g.