Pls someone help I need this urgently done

Question

asked Jul 21, 2023 159k views

1 Answer

Vanji · Answer 1 · 2023-07-26T07:21:06+0000

Answer:

p=3 and
q=4 the mistake was in calculating
3q-4q-10=6 let's solve first.

Explanation:

if
p= 2q-5 , substitute the
in the equation
3q-2p=6 as

3q-2(2q-5)=6

solve the equation in parentheses :

$3q-2(2q-5)\\$

multiply
$-2 \\$ by
$(2q-5)\\$ it will equal to:
3q-4q+10

now we want to let all unknown digits alone, so we will take
to the other side with a different sign it will be as:

3q-4q=6-10

now we will solve it:

$3q-4q=6-10\\q=-4$ at this part, the given equation was wrong in the paper.

we don't want the digit to be negative so we will do it like this:

(-q)/(-1) =(-4)/(-1 ) = q=4

now that we found
we will substitute it to find
$p\\$ :

$p=2q-5\\q=4\\p=2(4)-5\\p=8-5\\p=3$

overall the mistake was in calculating
instead of putting
3q-4q=6-10

he/she put a different sign in front of the digit like :
3q-4q-10=6

so when he/she flipped
it became positive and instead of subtracting he/she added it.