Question

Ammonium chloride is produced in the thermochemical equation NH3 (g) + HCl (g) → NH4Cl (s) ΔH = –176 kJ. How many moles of NH4Cl have been produced if the change in enthalpy is –528 kJ? You may use a calculator.

Answer 1

3.00 mol NH₄Cl

Step-by-step explanation:

Step 1: Write the thermochemical equation for the production of ammonuim chloride

NH₃(g) + HCl(g) → NH₄Cl(s) ΔH = –176 kJ

Step 2: Calculate the number of moles of NH₄Cl produced if the change in enthalpy is –528 kJ

According to the balanced thermochemical equation, 176 kJ are released when 1 mole of NH₄Cl is produced. The moles of NH₄Cl produced if the change in enthalpy is –528 kJ is:

-528 kJ × 1 mol NH₄Cl/(–176 kJ) = 3.00 mol NH₄Cl