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Hello! I need some assistance with this homework question for precalculus, please?HW Q27

Hello! I need some assistance with this homework question for precalculus, please-example-1
User Chikei
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1 Answer

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The expression is given to be:


\log_55^(86)

Recall the rule of logarithms:


\log a^b=b\log a

Thus the expression becomes:


\log_55^(86)=86\log_55

Recall the rule:


\log_aa=1

Hence, we have the expression to be:


86\log_55=86

The answer is 86.

User Canilho
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