Question

The acceleration due to gravity on Mimas a moon on Saturn, is 0.066m/s^2 . Starting from rest how much time does it take for an object to fall 10m on Mimas?

Answer 1

The equation to obtain the vertical distance cobered by the object is,

`h=ut+(1)/(2)gt^2`

The acceleration due to gravity on saturn is 0.066 m/s2.

Plug in the known values,

`\begin{gathered} 10\text{ m=(0 m/s)t+}(1)/(2)(0.066m/s^2)t^2 \\ t^2=\frac{2(10\text{ m)}}{0.066m/s^2} \\ t=\sqrt[]{303.03s^2} \\ \approx17.4\text{ s} \end{gathered}`

Thus, the time taken by object to fall is 17.4 s.