Question

What’s the mid point of AB in the picture below

Answer 1

From the given linear graph, we would write out the co-ordinates of the points A and B first in the form of (x,y).

Thus, we have:

`\begin{gathered} A(-6,-4) \\ B(-3,3) \end{gathered}`

The mid-point of a line segment;

`\begin{gathered} A(x_1,y_1)\text{ and} \\ B(x_2,y_2) \end{gathered}`

is given as:

`((x_1+x_2)/(2),(y_1+y_2)/(2))`

Thus, we have:

`\begin{gathered} ((-6+(-3))/(2),(-4+3)/(2)) \\ ((-6-3)/(2),-(1)/(2)) \\ ((-9)/(2),-(1)/(2)) \\ (-4.5,-0.5) \end{gathered}`

Hence, the midpoint of the line segment AB is: ( -4.5, -0.5)