67.57g of calcium metal will be produced.
1st) We need the balanced reaction and the molar mass of calcium hydroxide and calcium metal:
![2Ti+3Ca(OH)_2\text{ }\rightarrow2Ti(OH)_3\text{ + 3 Ca}](https://img.qammunity.org/2023/formulas/chemistry/college/lxghhij8kqisysnsebsz2ryb7fiy9ktylh.png)
- Ca molar mass: 40 g/mol
- Ca(OH)2 molar mass: 74 g/mol
According to the balanced reaction, we know that 3 moles of calcium hydroxide produces 3 moles of calcium metal.
With the molar mass of the compounds we can convert moles to grams, so we can see that 222g of calcium hydroxide (3 x 74g) can produce 120g of calcium metal (3 x 40g).
2nd) Now we can calculate the amount of calcium metal that will be produced from 125 grams of calcium hydroxide, with a mathematical Rule of Three:
![\begin{gathered} 222gCa(OH)_2-120gCa \\ 125gCa(OH)_2-x=(125g\cdot120g)/(222g) \\ x=67.57gCa \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/3ou9gqulhudhbrmsd6r0ejm6zzfo9b6at1.png)
Finally, 67.57g of calcium metal will be produced from 125g of calcium hydroxide.