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Solve by substitution x+2y-z = 4 3x – y +z = 5 2x + 3y + 2z = 7
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Solve by substitution x+2y-z = 4 3x – y +z = 5 2x + 3y + 2z = 7

User Pokaboom
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You have the following system of equations:

User Razlebe
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