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Preform the indicated Operation g(n)=2n^2-4nh(n)=n-1find g(h(1-b))

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GIven:

The expressions are given as,


\begin{gathered} g(n)=-2n^2-4n \\ h(n)=n-1 \end{gathered}

The objective is to find g(h(-1-b)).

Step-by-step explanation:

To find h(-1-b):

The value of h(-1-b) can be calculated by replacing the n with (-1-b) in the expression of h(n).


\begin{gathered} h(n)=n-1 \\ h(-1-b)=-1-b-1 \\ h(-1-b)=-2-b\text{ . . . . . . (1)} \end{gathered}

To find g(h(-1-b)):

The value of g(h(-1-b)) can be calculated by replacing the n with h(-1-b) in the expression g(n).


\begin{gathered} g(n)=-2n^2-4n \\ g(h(-1-b))=-2(-2-b)^2-4(-2-b)\text{ . . . . (2)} \end{gathered}

On further solving the equation (2),


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