Question

12. A block of ice is in theshape of a cube with sidelengths of 1.8 inches. The icehas a density of 876 kg percubic inch. Find the mass ofthe block of ice to the nearesttenth of a kg.

Answer 1

Step 1:

In this question, we are given the following:

A block of ice is in the shape of a cube with side lengths of 1.8 inches.

The ice has a density of 876 kg per cubic inch.

Find the mass of the block of ice to the nearest tenth of a kg.

Step 2:

The details of the solution are as follows:

Recall that:

`\begin{gathered} Density\text{ = }(Mass)/(Volume) \\ where\text{ Volume of the cube = length x length x length} \\ Volume\text{ of the cube = 1. 8 x 1. 8 x 1. 8 = 5.832 inches}^3 \end{gathered}`
`Density\text{ = 876 kg per cubic inch}`
`\begin{gathered} Therfore,\text{ mass of of the block of ice = Density x volume} \\ Mass\text{ of the bolock of ice = 876 x 5.832 = 5108. 832 kg}\approx\text{ 5108.8 kg} \\ (\text{ to the nearest tenth of a kg \rparen} \end{gathered}`

CONCLUSION:

The mass of the block of ice to the nearest tenth of a kg =

`5108.8\text{ kg }`