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This statics question has me stumped if you could hope me I would rlly appreciate it! Have a nice night :).

This statics question has me stumped if you could hope me I would rlly appreciate-example-1
User Elpidio
by
6.5k points

1 Answer

6 votes

Spinner A

Sample space = 1,2,3,4,5,6

Number of total outcome = 6

Odd numbers = 1,3,5

Number of odd numbers = 3


\text{Probability = }\frac{n\text{umber of required outcomes}}{\text{total number of possible outcome}}

Probability of spinning an odd number = 3/6 = 1/2

Spinner B

Sample space = yellow, brown, red

Number of total outcome = 3

Not yellow = brown, red

Number of not yellow = 2

Probability of not yellow = 2/3

Since the two spinners are independent events, then the probability that you spin an odd number and not yellow are multiplied together

Thus we have,

Probability of spinning an odd number X Probability of not yellow


(1)/(2)\text{ X }(2)/(3)\text{ = }(2)/(6)

Final answer is 1/3.

User Cura
by
6.4k points
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