Let us call x the number of $25 seats and y $40 seats, then we know that there are in total 5000 seats in a theatre; therefore, we have the equation
![x+y=5000](https://img.qammunity.org/2023/formulas/mathematics/college/xlfs0vefx5f89i1qxl30ffs7xse5cg2uw1.png)
Also, after selling this many tickets the total revenue should be $149, 000; therefore, we get the equation
![25x+40y=149,0000](https://img.qammunity.org/2023/formulas/mathematics/college/u2yb2x8kuai26b2he7bufie4p4ar0cd44m.png)
Hence, we have a system of equations with two equations and two unknowns.
We solve this system by substitution.
First, we solve for x in the first equation to get
![x=5000-y](https://img.qammunity.org/2023/formulas/mathematics/college/elq1f6cqlmsvi2037ubo3cm99mwhgvf4k4.png)
we then put this into the second equation to get
![25(5000-y)+40y=149,000](https://img.qammunity.org/2023/formulas/mathematics/college/fxtd9cr3nc32dxwfa7eipj4688wbhesxby.png)
![\rightarrow125,000-25y+40y=149,000](https://img.qammunity.org/2023/formulas/mathematics/college/m4su6a59x7v1q8clzwftmk011ahpsssebl.png)
![\rightarrow125,000+15y=149,000](https://img.qammunity.org/2023/formulas/mathematics/college/6knachwzfv0hrgi89lg9swnk1dhzel0ilq.png)
![\rightarrow15y=24,000](https://img.qammunity.org/2023/formulas/mathematics/college/2a5ngv4ce6ycpjg7zo6daq560izv3x7aym.png)
![\therefore y=1600.](https://img.qammunity.org/2023/formulas/mathematics/college/1qk9fgdqkveeiohjkhxccyr1ika9xyqqaa.png)
Now that we have y, we now solve for x to get:
![x=5000-1600](https://img.qammunity.org/2023/formulas/mathematics/college/r9gkrhhlhnnv2msr7to2xr82naw6o0tca2.png)
![x=3400.](https://img.qammunity.org/2023/formulas/mathematics/college/k0g8o7ym5fktea9ghv4mfnwb37uy9irlof.png)
Hence x = 3400 and y = 1600 and the correct statements are as follows.
The number of tickets for sale at $25 should be 3400.
The number of tickets for sale at $40 should be 1600.