Question

Object A, which has been charged to +13.13 nC, is at the origin. Object B, which has been charged to -26.7 nC, is at x=0 and y=2.72 cm. What is the magnitude of the electric force on object A?

Answer 1

0.004259 N

Explanation:

Given:

qA = +13.13 nC

qB = -26.7 nC

d = y - x = 2.72 - 0 = 2.72 cm = 0.0272 m

We use Coulomb's law to calculate the force:

`F=k\cdot(q_A\cdot q_B)/(d^2)`

We substitute each value and calculate the force:

`\begin{gathered} F=9*10^9\cdot((13.13*10^(-9))(26.7*10^(-9)))/((0.0272)^2) \\ \\ F=0.004259\text{ N} \end{gathered}`

The magnitude of the electric force on object A is 0.004259 N