Question

If a golden rectangle has a length of 1 cm, what is its width (shorter side) rounded to the NEAREST TENTH?

Answer 1

In any golden rectangle the following poreperty should hold:

`(a+b)/(a)=(a)/(b)`

where a+b is the length and a is the width. We know that the length of the rectangle is 1, then:

`\begin{gathered} a+b=1 \\ b=1-a \end{gathered}`

Plugging this values in the first equation we have:

`(1)/(a)=(a)/(1-a)`

Solving this equation for a: