136k views
4 votes
(300/m) + 44n m=15 n=4

User Erison
by
8.3k points

1 Answer

3 votes

Solve (300/m) + 44n where m = 15 and n = 4


\begin{gathered} ((300)/(m))+44n \\ \text{Substitute for the values of m and n, and you have;} \\ ((300)/(15))+44(4) \\ 20+176 \\ 196 \end{gathered}

The solution to the expression is 196

User Shenequa
by
8.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories