The y-intercept is (0,-3) while the x-intercept is (18.75,0)
Here, we want to find the x and y-intercepts of the given line
Firstly, we have to rewrite the equation of the line in the standard form
We have this as;
![\text{y = mx + b}](https://img.qammunity.org/2023/formulas/mathematics/college/shmcf4g1fpjaa78zknladrzkwfzwbnm8nz.png)
m is the slope and b is the y-intercept
Rewriting the given equation, we have this as;
![\begin{gathered} 5y\text{ = 4x-15} \\ y\text{ =}(4)/(5)x-(15)/(5) \\ \\ y\text{ = }(4)/(5)x\text{ - 3} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/xpagt0jvnpp9yvnmwcmadxdeg6yb8k37az.png)
We have the y-intercept as -3
In the coordinate form, this is (0,-3)
To get the x-intercept, we set the y value to zero
We have this as;
![\begin{gathered} 0\text{ = }(4)/(5)x-15 \\ 15\text{ = }(4x)/(5) \\ \\ 4x\text{ = (15}*5) \\ 4x\text{ = 75} \\ x\text{ = }(75)/(4) \\ x\text{ = 18.75} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/l6vxt6hd0725m2bbq0ehlttr0aeos5iqlc.png)
The x-intercept is 18.75 which in the coordinate form is (18.75,0)