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I need to know the steps to solve this equation using the quadratic formula.

I need to know the steps to solve this equation using the quadratic formula.-example-1
User Foundry
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Given a quadratic equation with the following form


ax^2+bx+c=0

By the quadratic formula, the solutions are given by the following expression


x_(\pm)=(-b\pm√(b^2-4ac))/(2a)

In our problem we have the following equation


4x^2-7x+3=0

Therefore, our coefficients are


\begin{gathered} a=4 \\ b=-7 \\ c=3 \end{gathered}

Plugging those values into the quadratic formula, we have


x_(\pm)=(-(-7)\pm√((-7)^2-4(4)(3)))/(2(4))

Solving this equation, we have


\begin{gathered} x_{\operatorname{\pm}}=(-(-7)\pm√((-7)^2-4(4)(3)))/(2(4)) \\ =(7\pm√(49-48))/(8) \\ =(7\pm1)/(8) \\ \implies\begin{cases}x_+={1} \\ x_-={(3)/(4)}=0.75\end{cases} \end{gathered}

User Lucas Rezende
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