Question

Hi, can you help me to solve this problem, please!!!

Answer 1

The given parabola is:

`y=-3x^2+3x-6`

It is written in the form:

`y=ax^2+bx+c`

The axis of symmetry is given by the following formula:

`x=-(b)/(2a)`

Where a=-3 and b=3. Replace these values and solve for x:

`\begin{gathered} x=-(3)/(2(-3))=-(3)/(-6)=(3)/(6) \\ \text{Divide numerator and denominator by 3 to simplify} \\ x=(3/3)/(6/3)=(1)/(2) \end{gathered}`

Therefore, the axis of symmetry is x=1/2