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Find the sum of 5 even positive integers

User Valgog
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sum of 5 even positive integers


n+(n+2)+(n+4)+(n+6)+(n+8)

here, n is the first even number,

let's simplify this,


\begin{gathered} =n+n+2+n+4+n+6+n+8 \\ =5n+20 \end{gathered}

Thus the expression to find the sum of 5 consecutive even positive integers is, 5*n + 20 , where n is the 1st even positive integer.

let's use it when n = 2 or to sum 2, 4, 6, 8 and 10


5*2+20=10+20=30

which is the same as,


2+4+6+8+10=30

User Siraris
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