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What’s the equation for points (2,13) and (4,6)

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The points we have are:

(2,13) and (4,6)

I will label this points as follows:


\begin{gathered} x_1=2 \\ y_1=13 \\ x_2=4 \\ y_2=6 \end{gathered}

To find the equation for this line, first we need to find the slope between the points with following slope formula:


m=(y_2-y_1)/(x_2-x_1)

Where m is the slope.

Substituting our known values:


\begin{gathered} m=(6-13)/(4-2) \\ m=(-7)/(2) \end{gathered}

Next, we need to use the point-slope equation:


y=m(x-x_1)+y_1

And substitute our values, including the slope:


y=-(7)/(2)(x-2)+13

Using the distributive property to multiply -7/2 by x and by -2:


\begin{gathered} y=-(7)/(2)x+7+13 \\ y=-(7)/(2)x+20 \end{gathered}

Answer:


y=-(7)/(2)x+20

User Lori
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