Question

Find X and y intercepts 7x+10y=40

Answer 1

To find the intercept of the function on the x-axis, replace y = 0 and solve for x:

`\begin{gathered} y=0 \\ 7x+10y=40 \\ 7x+10(0)=40 \\ 7x+0=40 \\ 7x=40 \\ \text{ Divide by 7 from both sides of the equation} \\ (7x)/(7)=(40)/(7) \\ x=(40)/(7) \end{gathered}`

Therefore, the x-intercept of the function is in the ordered pair:

`((40)/(7),0)`

To find the intercept of the function on the y-axis, replace x = 0 and solve for y:

`\begin{gathered} x=0 \\ 7(0)+10y=40 \\ 0+10y=40 \\ 10y=40 \\ \text{ Divide by 10 from both sides of the equation} \\ (10y)/(10)=(40)/(10) \\ y=4 \end{gathered}`

Therefore, the y-intercept of the function is in the ordered pair:

`(0,4)`