Let us assume the numbers are x and y.
The first part of the question can be written as
![x+y=200\text{ ---------------(1)}](https://img.qammunity.org/2023/formulas/mathematics/college/rtev9dstxm0blzycpwl16fbmvdt3jmh0bx.png)
and the second part can be written as
![x-y=28\text{ --------------(2)}](https://img.qammunity.org/2023/formulas/mathematics/college/m9hpm08dcyz1p5n5239ufe5n6nq4fcbvn6.png)
From equation 1, we can get a value for y as
![y=200-x\text{ -------------(3)}](https://img.qammunity.org/2023/formulas/mathematics/college/ctj6d5rwp02845dz59vvcps8bnch0canhi.png)
Substitute for y in equation 3 into equation 2:
![x-(200-x)=28](https://img.qammunity.org/2023/formulas/mathematics/college/9psizd28n53ujfq1eb443co3oz6x7mmcwn.png)
Expanding and solving, we get
![\begin{gathered} x-200+x=28 \\ 2x=200+28 \\ 2x=228 \\ \therefore \\ x=(228)/(2) \\ x=114 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/pkruxjchz50z5e5isvm1tex0banqmm7cav.png)
Next, we substitute for the value of x into equation 3:
![\begin{gathered} y=200-114 \\ y=86 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3723uxmu21h9svqkbhgunqhyulhbbrhd8k.png)
Therefore, the two numbers are 114 and 86