We must substitute each pair into our equation:
A. If we substitute point (1,1), we have

then, this point is a solution.
B. If we substitute point (-1,1), we have

this means that this point is not a solution.
C. If we substitute point (-6,7), we have

this means that this point is not a solution.
D. If we substitute point (3,-11), we have

then, this point is a solution.
Therefore, the solutions are option A and D