The product of the sum and difference binomials is

We will use this rule to solve the question
We need to find the product of (a - 1) and (2a + 2)
At first, we will take 2 as a common factor from the second bracket

Now, we will multiply (a - 1) by 2(a + 1)

By using the rule of the product of the sum and difference above, then

The answer is B