Question

Someone pls help! mathematics.

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The formula for any geometric sequence is an = a1 · rn - 1 , where an represents the value of the n th term, a1 represents the value of the first term, r represents the common ratio, and n represents the term number. What is the formula for the geometric sequence 4, 8, 16, 32, ...?

an = 4 · ( ) n - 1
an = 2 · 4 n - 1
an = 32 · 2 n - 1
an = 4 · 2 n - 1

Answer 1

a(n) = 4*(2)^(n - 1)

Explanation:

The correct version of this formula is a(n) = a(1)*r^(n - 1). Must use the " ^ " symbol to indicate exponentiation, and enclose the "n - 1" inside parentheses.

Here, if 4, 8, 16, 32, ..., then a(1) = 4 and r = 2 (e. g., 16/8 = 2, 32/2 = 16, and so on).

Then the correct formula for this geometric sequence is

a(n) = 4*(2)^(n - 1), where use of the parentheses as indicated is mandatory.

Answer 2

a(n) = 4*(2)^(n - 1)

Explanation:

The correct version of this formula is a(n) = a(1)*r^(n - 1). Must use the " ^ " symbol to indicate exponentiation, and enclose the "n - 1" inside parentheses.

Here, if 4, 8, 16, 32, ..., then a(1) = 4 and r = 2 (e. g., 16/8 = 2, 32/2 = 16, and so on).

Then the correct formula for this geometric sequence is

a(n) = 4*(2)^(n - 1), where use of the parentheses as indicated is mandatory.