Question

3x – 2y= 12Find the x- and y-intercepts from the equation in standard form above. Explain how you got each intercept.

Answer 1

To find the y-intercept, we have to make x=0 and solve for y:

`\begin{gathered} 3x-2y=12 \\ x=0 \\ \Rightarrow3\cdot0-2y=12 \\ \Rightarrow-2y=12 \\ \Rightarrow y=(12)/(-2)=-6 \\ y=-6 \end{gathered}`

Now, to find the x-intercept, we make y=0 and do the same as the previous case:

`\begin{gathered} y=0 \\ \Rightarrow3x-2\cdot0=12 \\ \Rightarrow3x=12 \\ \Rightarrow x=(12)/(3)=4 \\ x=4 \end{gathered}`

therefore, the y-intercept is the point (0,-6) and the x-intercept is the point (4,0)