Question

Express sin 285 as a function of the reference angle.Question 19 options:sin75sin105-sin75sin-75

Answer 1

Given:

`\sin 285^(\circ)`

To express it as a function of reference angle:

Since the angle lies in the fourth quadrant.

So, the reference angle will be,

`\begin{gathered} \theta_(ref)=360-\theta_4 \\ \theta_(ref)=360^(\circ)-285 \\ \theta_(ref)=75^(\circ) \end{gathered}`

Therefore, the function of the reference angle is,

`\sin 75^(\circ)`