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Any help is greatly appreciated!

Any help is greatly appreciated!-example-1
User EliadL
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1 Answer

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5 votes

Answer:

Equation of the line in point-slope form: y - 5 = -⅚(x - 2)

Equation of the line in slope-intercept form: y = -⅚x + 20/3

Explanation:

Equation of a line can be expressed in the point-slope form as y - b = m(x - a), where,

m = slope = -⅚

a = 2

b = 5

Substitute the values into y - b = m(x - a):

y - 5 = -⅚(x - 2) => point-slope form.

We can rewrite this in the slope-intercept form, such as:

Multiply both sides by 6

6(y - 5) = -5(x - 2)

6y - 30 = -5x + 10

6y - 30 + 30 = -5x + 10 + 30

6y = -5x + 40

Divide both sides by 6

y = -5x/6 + 40/6

y = -⅚x + 20/3

User Ecnalyr
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