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How many grams are in 4.02 x 10^21 atoms of calcium?

1 Answer

5 votes

Answer:

0.268grams

Explanations:

According to the Avogadro's constant

1 mole of an atom = 6.02 * 10^23 molecules

Given the following

atoms of calcium = 4.02 x 10^21 atoms

Determine the moles of calcium


\begin{gathered} moles\text{ of Ca}=(4.02*10^(21))/(6.02*10^(23)) \\ moles\text{ of Ca}=0.668*10^(21-23) \\ moles\text{ }of\text{ Ca}=0.668*10^(-2) \\ moles\text{ of Ca}=0.00688moles \end{gathered}

Determine the mass of Calcium


\begin{gathered} Mass=mole* molar\text{ mass} \\ Mass=0.00688*40.078 \\ Mass\text{ of Ca}=0.268gram \end{gathered}

Hence the required grams in 4.02 x 10^21 atoms of calcium is 0.268grams

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