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6ft 3ft 8ft 16ft area of irregular figures

User Esilac
by
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1 Answer

3 votes

Solution.

From the figure given we will have to find the

(Area of A) + (The Area of B)

STEP 1 :

For figure B

b = 3

h = 6


\begin{gathered} \text{Area of A = }(1)/(2)* b* h \\ \text{ = }(1)/(2)*3*6 \\ \text{ = }(18)/(2)\text{ = 9} \end{gathered}

Step 2:

For Figure A

L = 16

b = 8ft

Area of B = L x B

= 16 x 8

= 128

STEP 3

Area of A + Area of B

128 + 9 = 137 square feet

6ft 3ft 8ft 16ft area of irregular figures-example-1
User Mik
by
3.7k points