Given the reaction:
![2HNO_3+Ca(OH)_2\to Ca(NO_3)_2+2H_2O](https://img.qammunity.org/2023/formulas/chemistry/college/7hxl4l7zuvmdx8t15xfl8cpsxenhjrtwtr.png)
We're going to write a net ionic equation for this reaction as follows:
1. First, write the total ionic equation:
![^{}Ca^(2+)_(aq)+2OH^-_(aq)+2H^+_{aq_{}}+2NO^-_3\to^{}Ca^(2+)_(aq)+2NO^-_3+2H_2O](https://img.qammunity.org/2023/formulas/chemistry/college/tnq4n1t0g9l63zt4bjxmlvh6iof4ioyot4.png)
2. Now, we could cancel the same type of ions that are in both sides of the reaction. Therefore, the net ionic equation is:
![H^+_(aq)+^{}OH^-_(aq)\to H_2O_((l))](https://img.qammunity.org/2023/formulas/chemistry/college/vb7ynpvn8tc1bglolwkds7kxxpjk8bk5w2.png)