Question

How do you solve an area of a rectangle with fractions

Answer 1

Given the figure, we can deduce the following information:

Perimeter = 65 in.

length = n

width = 11 2/4 in. = 23/2 in.

To determine the value of n, we use the formula:

`P=2(l+w)`

where:

P= Perimeter

l=length

w=width

We plug in what we know:

`\begin{gathered} P=2(l+w) \\ 65=2(n+11(2)/(4)) \\ \text{Simplify and rearrange} \\ 65=2(n+(23)/(2)) \\ (65)/(2)=n+(23)/(2) \\ n=(65)/(2)-(23)/(2) \\ n=(65-23)/(2) \\ n=(42)/(2) \\ \text{Calculate} \\ n=21 \end{gathered}`

Therefore, the value of n is 21 in.