The rate of change of a linear functions is given by:
![m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/78uaqhwt0aws3qfwxigaftpihnmb1gzxtp.png)
where (x1,y1) and (x2,y2) are points through the graph.
Function 1.
From the table we have that the functions passes through the points (-11,8) and (-7,13), pluggin the values in the formula above we have:
![\begin{gathered} m=(13-8)/(-7-(-11)) \\ m=(5)/(11-7) \\ m=(5)/(4) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/jnlr007puxlpxb0okzfostoy0xjt31aq89.png)
Therefore the rate of change of functions 1 is 5/4
Function 2.
From the graph we notice that the functions passes through the points (-3,-4) and (1,-1), hence:
![\begin{gathered} m=(-1-(-4))/(1-(-3)) \\ m=(-1+4)/(1+3) \\ m=(3)/(4) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/yy6mdinfq9liebbckgdsgquomg996zela5.png)
Therefore the rate of change of function 2 is 3/4.
Comparing both rates of change we conclude that Function 1 has the greater change of rate.