Given:
![\begin{gathered} 4x+3y=12 \\ 4x-3y=12 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/etujxq03rscghp2dgr5uileoehrf90h69a.png)
Required:
To solve the system of equation using graph and to state whether the system is dependent, independent, or inconsistent.
Step-by-step explanation:
Consider the equation
![4x+3y=12](https://img.qammunity.org/2023/formulas/mathematics/college/4s4gg7v4w0wv03sluxj5ntcpsko5gtpjpq.png)
When x=0,
![\begin{gathered} 0+3y=12 \\ 3y=12 \\ y=(12)/(3) \\ y=4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/vgzi5ey5k7sf3l3ynxlk3zcx44s66awm2v.png)
When x=3,
![\begin{gathered} 12+3y=12 \\ 3y=12-12 \\ 3y=0 \\ y=0 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/r1ni6k7bbwd3rk9nvry1lglamxlekmnjeq.png)
Now consider the equation
![4x-3y=12](https://img.qammunity.org/2023/formulas/business/high-school/fh3rlardgb9z6ehmn9m7xoiv2th4lovmoh.png)
When x=0,
![\begin{gathered} 0-3y=12 \\ -3y=12 \\ y=-(12)/(3) \\ y=-4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ckyskwy583b5q1gy0sc8h7prkk01s1en89.png)
When x= 3,
![\begin{gathered} 12-3y=12 \\ -3y=12-12 \\ -3y=0 \\ y=0 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/auqf187ttkhqz9yy506p8y464mgrr1fbfu.png)
The graph of the given system of equation is,
The blue graph is graph of 4x+3y=12 and the black graph is graph of
4x-3y=12.
The two line crosses at the point (3,0).
Therefore the solution is
![\begin{gathered} x=3 \\ y=0 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/262u8871wa5i2xk0azhihnz6o11pscjzid.png)
Here the solution is one.
Therefore the consistent system has exactly one solution, it is independent .
Final Answer:
The solution of the given system of equation is
![\begin{gathered} x=3 \\ y=0 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/262u8871wa5i2xk0azhihnz6o11pscjzid.png)
The consistent system has exactly one solution, it is independent .