Question

2 radical 6 minus -2 radical 24 adding and subtracting radicals

Answer 1

`2\sqrt[]{6}-2\sqrt[]{24}t`

Substraction:

1. Find prime factors of 24

`\sqrt[]{24}=\sqrt[]{2^2\cdot6}`

2. As 2 squared has a exact square root extract it from the radical:

`\sqrt[]{24}=2\sqrt[]{6}`

Then, you have the next expression:

`\begin{gathered} 2\sqrt[]{6}-2\sqrt[]{24}=2\sqrt[]{6}-2(2\sqrt[]{6}) \\ \\ =2\sqrt[]{6}-4\sqrt[]{6} \end{gathered}`

Substract similar terms (taking square root of 6 as a common factor):

`\begin{gathered} =(2-4)\cdot\sqrt[]{6} \\ \\ =-2\sqrt[]{6} \end{gathered}`